Answer:
a) q = 39.29 cm ,  b)  h ’= - 3.929 cm  the image is inverted  and REAL
Explanation:
For this exercise we will use the equation of the constructor
     1 / f = 1 / p + 1 / q
where f is the focal length of the salad bowl, p and q are the distance to the object and the image
The metal salad bowl behaves like a mirror, so its focal length is
      f = R / 2
      f = 44/2
      f = 22 cm
a) Suppose that the distance to the object is p = 50 cm, let's find the distance to the image
      1 / q = 1 / f  - 1 / p
      1 / q = 1/22 - 1/50
      1 / q = 0.0254
      q = 39.29 cm
b) to calculate the size of the image we use the equation of magnification
      m = h’/ h = - q / p
      h ’= - q / p h
      h ’= - 39.29 / 50 5
      h ’= - 3.929 cm
the negative sign means that the image is inverted
as the rays of light pass through the image this is REAL
