Answer:
a
[tex]E_g = 240 \ kWh [/tex]
b
[tex]N = 144 \ meals [/tex]
Explanation:
From the question we are told that
The power rating of the bulb is P = 100 W
The duration is t = 1 month = 1 * 30 * 24 = 720 h
The efficiency is [tex]\eta = 30\% = 0.30[/tex]
The fuel consumption for one meal is [tex]E = 6 MJ = 6 *10^6 J[/tex]
Generally the energy consumed by the bulb is mathematically represented as
[tex]E_c = P * t[/tex]
=> [tex]E_c = 100 * 720 [/tex]
=> [tex]E_c = 72\ k Wh [/tex]
Generally the energy generated at the power plant that was wasted by the bulb is mathematically represented as
[tex]E_g = \frac{E_c}{\eta}[/tex]
=> [tex]E_g = \frac{72000}{0.3}[/tex]
=> [tex]E_g = 240 \ kWh [/tex]
Converting this value to Joules
[tex]E_g = 240 * 3.6 * 10^{6} = 8.64*10^8 [/tex]
Generally the number of means that would be cooked is
[tex]N = \frac{8.64*10^8 }{6 *10^6}[/tex]
=> [tex]N = 144 \ meals [/tex]
The wasted chemical energy be "8.64 × 10⁸ J" and the equivalent meals could be cooked be "144".
According to the question,
Bulb power, P = 100 W
Time, t = 1 month or,
= 1 × 30 × 24
= 720 h
Efficiency, η = 30% or,
= 0.30
Fuel consumption, E = 6 MJ or,
= 6 × 10⁶ J
Energy consumed be:
→ [tex]E_c[/tex] = P × t
By substituting the values,
= 100 × 720
= 72 kWh
Wasted energy be:
→ [tex]E_g[/tex] = [tex]\frac{E_c}{\eta}[/tex]
= [tex]\frac{72000}{0.3}[/tex]
= 240 kWh or,
= 240 × 3.6 × 10⁶
= 8.64 × 10⁸ J
and,
The no. of meals be:
→ N = [tex]\frac{8.64\times 10^8}{6\times 10^6}[/tex]
= 144 meals
Thus the answers above are correct.
Find out more information about chemical energy here:
https://brainly.com/question/347340
