If the coins are selected without replacement, the probability of 2 dimes is:[tex]\frac{5}{8}\times\frac{4}{7}=\frac{5}{14}[/tex]
The answer is 5/14.
Using the formula for a hypergeometric distribution, we get:
[tex]P(2\ dimes)=\frac{5C2\times3C0}{8C2}=\frac{5}{14}[/tex]
