2021ecarter
contestada

Solve 3x^2 + 17x - 6 = 0.
3x2 + 18x - x- 6 =0

3x(x+6) -1(x+6) =0

(3x-1)(x+6) =0

3x-1 or x+6 =0


Based on the work shown above, which of these values are possible solutions of the equation? Check all of the boxes that apply.


x=-6

x=6

x=-β…“

x=β…“

x=0

Respuesta :

zycholm23

Answer:

3x^2+17x-6=0.

a = 3; b = 17; c = -6;

Ξ” = b2-4ac

Ξ” = 172-4Β·3Β·(-6)

Ξ” = 361

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=βˆ’bβˆ’Ξ”βˆš2ax2=βˆ’b+Ξ”βˆš2a

Ξ”βˆ’βˆ’βˆš=361βˆ’βˆ’βˆ’βˆš=19

x1=βˆ’bβˆ’Ξ”βˆš2a=βˆ’(17)βˆ’192βˆ—3=βˆ’366=βˆ’6

x2=βˆ’b+Ξ”βˆš2a=βˆ’(17)+192βˆ—3=26=1/3

Step-by-step explanation:

maxisacow

Answer:

-6 and 1/3

Step-by-step explanation:

Otras preguntas