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Karissa is conducting an experiment on the amount of salt that dissolves in water at different temperatures. She repeats her tests several times using the same procedure.
What can Karissa do to further increase confidence in the results of her experiment?

1.have another scientist run the same exact procedure in her lab

2.include several other liquids for comparison

3.calculate the average amount of salt that dissolves to summarize findings

4.make sure the experiment follows a specific procedure that allows other scientists to produce the same findings

Respuesta :

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Valid Expressions are; t = āˆ›(dĀ²/va), a = d/tĀ², a = āˆš(vd/tĀ³), v = at

while the Invalid expressions are; Ā v = a/t and Ā d = at

Explanation:

Given expressions

1) v = a/t

2) t = āˆ›(dĀ²/va)

3) d = at

4) a = d/tĀ²

5) a = āˆš(vd/tĀ³)

6) v = at

First we get our units of parameters

V = m/s, t = sec, d = m, a = m/sĀ²

so

1)

v = a/t

we substitute in our units of parameters

v = m/sĀ² / s = m/sĀ² Ɨ 1/s = m/sĀ³

v ā‰  m/sĀ³

therefore it is false

2)

t = āˆ›(dĀ²/va)

we substitute

t = āˆ›(mĀ² / m/s Ɨ m/sĀ²)

t = āˆ›(mĀ² / mĀ²/sĀ³)

t = āˆ›(sĀ³)

t = s

correct, the expression is true

3)

d = at

we substitute

d = m/sĀ² Ɨ s

d = m/sĀ² Ɨ s/1 = Ā ms/sĀ² = m/s

d ā‰  m/s (because d = m)

so expression is false

4)

a = d/tĀ²

we substitute

a = m / sĀ² = m/sĀ²

correct

the expression is true

5)

a = āˆš(vd/tĀ³)

we substitute

a = āˆš(m/sƗm / sĀ³) = āˆš(mĀ²/s / sĀ³) = āˆš(mĀ²/s Ɨ 1/sĀ³) Ā = āˆš(mĀ²/sā“) = m/sĀ²

so a = m/sĀ²

correct

the expression is true

6)

v = at

we substitute in the units

v = m/sĀ² Ɨ s = m/sĀ² Ɨs/1 = ms/sĀ² = m/s

v = m/s

correct

the expression is correctValid Expressions are; t = āˆ›(dĀ²/va), a = d/tĀ², a = āˆš(vd/tĀ³), v = at

while the Invalid expressions are; Ā v = a/t and Ā d = at

Explanation:

Given expressions

1) v = a/t

2) t = āˆ›(dĀ²/va)

3) d = at

4) a = d/tĀ²

5) a = āˆš(vd/tĀ³)

6) v = at

First we get our units of parameters

V = m/s, t = sec, d = m, a = m/sĀ²

so

1)

v = a/t

we substitute in our units of parameters

v = m/sĀ² / s = m/sĀ² Ɨ 1/s = m/sĀ³

v ā‰  m/sĀ³

therefore it is false

2)

t = āˆ›(dĀ²/va)

we substitute

t = āˆ›(mĀ² / m/s Ɨ m/sĀ²)

t = āˆ›(mĀ² / mĀ²/sĀ³)

t = āˆ›(sĀ³)

t = s

correct, the expression is true

3)

d = at

we substitute

d = m/sĀ² Ɨ s

d = m/sĀ² Ɨ s/1 = Ā ms/sĀ² = m/s

d ā‰  m/s (because d = m)

so expression is false

4)

a = d/tĀ²

we substitute

a = m / sĀ² = m/sĀ²

correct

the expression is true

5)

a = āˆš(vd/tĀ³)

we substitute

a = āˆš(m/sƗm / sĀ³) = āˆš(mĀ²/s / sĀ³) = āˆš(mĀ²/s Ɨ 1/sĀ³) Ā = āˆš(mĀ²/sā“) = m/sĀ²

so a = m/sĀ²

correct

the expression is true

6)

v = at

we substitute in the units

v = m/sĀ² Ɨ s = m/sĀ² Ɨs/1 = ms/sĀ² = m/s

v = m/s

correct

the expression is correct

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