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A ball is released from the top of a 2-meter long ramp and rolls down with a uniform acceleration of 3 m/s^2.
a. How fast is the ball moving when it reaches the bottom of the ramp?
b. How long does it take to roll down the ramp?

Respuesta :

MathPhys

Answer:

a. 3.46 m/s

b. 1.15 s

Explanation:

Given:

Δx = 2 m

v₀ = 0 m/s

a = 3 m/s²

a. Find v

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (3 m/s²) (2 m)

v = 3.46 m/s

b. Find t

Δx = v₀ t + ½ at²

2 m = (0 m/s) t + ½ (3 m/s²) t²

t = 1.15 s

Answer:

a. 3.46 m/s

b. 1.15 s

Explanation: