Answer:
about 42.35 m/s
Explanation:
Use the equation for accelerated motion (g), and with zero initial velocity that doesn't include time:
[tex]v_f^2=v_i^2+2\,a\,\Delta x[/tex]
which for our case would reduce to:
[tex]v_f^2=v_i^2+2\,a\,\Delta x\\v_f^2=0+2\,9.8\,(91.5)\\v_f^2= 1793.4\\v_f=\sqrt{1793.4} \\v_f \approx 42.35[/tex]
then the velocity just before hitting would be about 42.35 m/s
