Step-by-step explanation:
We start by calculating mean and standard deviation
Mean = sum of all values/total number of values
= 110.5/10
= 11.05
Standard deviation = √375.725/9
= √41.7472
= 6.46
Null hypothesis =
h0: μ = 14
Alternate hypothesis =
H1: μ < 14
Alpha is set at 0.05
Test statistic
T = mean - (μ)/(sd/√n)
=(11.05-14)/(6.46/√10)
= -2.95/2.0428
= -1.4441
P value calculator
df = n-1 = 10 -1 = 9
P Value = trust(x,df,tails)
= trust(1.4441,9,1)
= 0.0913
In conclusion our pvalue is greater than alpha level at 0.05 so we do not have sufficient evidence to reject the null hypothesis. We do not have enough evidence to accept the alternate so we reject claim that mean lead concentration for all such medicine is < than 14μg/g