Respuesta :
Answer:
a
[tex]\mu  =  127[/tex]
b
[tex]\sigma  =  9.76[/tex] Â
c
[tex]z-score  =  3.18 [/tex]
d
Yes, 158 players out of 508 is an unusual number of men born in the first 3 months of the year because the z score of 158  is  greater than  3( Note :the probability of  z-score = 3 is  97%)
e
The correct option is  option 3
Step-by-step explanation:
From the question we are told that
  The population proportion is  p =  0.25
  The sample size is  n =  508
 Â
Generally the mean is  mathematically represented as Â
   [tex]\mu  =  np[/tex]
=>  [tex]\mu  =  508 * 0.25[/tex]
=>  [tex]\mu  =  127[/tex]
Generally the standard deviation is mathematically represented as
   [tex]\sigma  =  \sqrt{ np (1-p)}[/tex]
=>  [tex]\sigma  =  \sqrt{ 508 * 0.25 (1-0.25)}[/tex]  Â
=>   [tex]\sigma  =  9.76[/tex] Â
Generally the z-score of  158 is mathematically represented as
  [tex]z-score  =  \frac{158 - 127}{9.76}[/tex]
=>  [tex]z-score  =  \frac{158 - 127}{9.76}[/tex]
=>  [tex]z-score  =  3.18 [/tex]
Yes, 158 players out of 508 is an unusual number of men born in the first 3 months of the year because the z score of 158  is  greater than  3( Note :the probability of  z-score = 3 is  97%)
What this means is that the almost the whole  professional hockey league player are born in the first month which is unusual