Answer:
a. 1,000 trees
b. 3,250 trees
Step-by-step explanation:
a. How many trees will they plant during the fifth year?
b. How many trees will they have planted by the end of the tenth year?​
Using the sum of an arithmetic progression formula
Sn = n/2 {2a+(n-1)d}
Where,
Sn = Sum of an n terms
n = number of terms
a = first term
d = common difference
a.
n = 5
a = 100
d = 50
S5 = n/2 {2a+(n-1)d}
= 5/2 {2*100 + (5-1)50}
= 5/2 {200+(4)50}
= 5/2{200 + 200}
= 5/2(400)
= 2,000 / 2
= 1,000
S5 = 1,000 trees
b. Sn = n/2 {2a+(n-1)d}
n = 10
a = 100
d =50
S10 = 10/2{2*100 + (10-1)50}
= 5{200 + (9)50}
= 5{200 + 450}
= 5(650)
= 3,250
S10 = 3,250 trees