Answer: There are 70 outcomes.
Step-by-step explanation:
The number of combinations for n things if r thing s have been chosen ( repetition is allowed) = [tex]C(n+r-1, n-1)[/tex]
Here , n= 5 , r= 4
The possible outcomes = [tex]C(5+4-1, 5-1)= C(8,4)[/tex]
As [tex]C(n,r)=\dfrac{n!}{r!(n-r)!}[/tex]
So, The possible outcomes = [tex]\dfrac{8!}{4!(8-4)!}[/tex]
[tex]=\dfrac{8\times7\times6\times5\times4!}{4\times3\times2\times1\times4!}\\\\=70[/tex]
Hence, there are 70 outcomes.
