GIVING BRAINLIEST easy question
A bridge is 10 m above a railroad track and at right angles to it. A train is running at the rate of 20 m/s passes under the center of the bridge at the same instant that a car running 15 m/s reaches that point. How rapidly are they separating 3 seconds later?

Taking the point directly under the center of the bridge as the origin,
x = 20t, y = 15t, z = 10
let s be thedistance between them at time t,
s^2 = (20t)^2 + (15t)^2 + 10^2 = 625t^2 + 100
2s ds/dt = 1250t
ds/dt = 625t/s

when t = 3, s = √(625*9+100) = 75.6637
ds/dt = 625*3/75.6637 = 24.78 m/s

Answer Link

andromache andromache · Answer 2 · 2022-04-15T13:28:04+02:00

The time taken that should be rapidly are distinct 3 seconds later should be considered as 24.78 m/s.

Calculation of the time taken:

Here the point should be considered directly under the center of the bridge as the origin

Here

x = 20t, y = 15t, z = 10

let us assume s be the distance between them at time t,

So it be like

[tex]s^2 = (20t)^2 + (15t)^2 + 10^2 = 625t^2 + 100[/tex]

2s ds/dt = 1250t

ds/dt = 625t/s

Now at the time when

t = 3,

[tex]s = \sqrt (625*9+100)[/tex] = 75.6637

So,

ds/dt = [tex]625*3/75.6637[/tex] = 24.78 m/s

Learn more about time here: https://brainly.com/question/11325462

GIVING BRAINLIEST easy question A bridge is 10 m above a railroad track and at right angles to it. A train is running at the rate of 20 m/s passes under the center of the bridge at the same instant that a car running 15 m/s reaches that point. How rapidly are they separating 3 seconds later?

Respuesta :

Calculation of the time taken:

Otras preguntas

GIVING BRAINLIEST easy question
A bridge is 10 m above a railroad track and at right angles to it. A train is running at the rate of 20 m/s passes under the center of the bridge at the same instant that a car running 15 m/s reaches that point. How rapidly are they separating 3 seconds later?