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Use the following equation to answer question 1-4. Make sure you balance first.

6HCI + Fe2O3 --> 2FeCl3 +3H2O

1. How many moles of water are produced from 10.4 moles of hydrochloric acid? ​

Respuesta :

Space

Answer:

5.2 mol H₂O

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

[RxN - Balanced] 6HCl + Fe₂O₃ → 2FeCl₃ + 3H₂O

[Given] 10.4 mol HCl

Step 2: Identify Conversions

[RxN] 6 mol HCl = 3 mol H₂O

Step 3: Stoichiometry

  1. Set up:                             [tex]\displaystyle 10.4 \ mol \ HCl(\frac{3 \ mol \ H_2O}{6 \ mol \ HCl})[/tex]
  2. Multiply/Divide:               [tex]\displaystyle 5.2 \ mol \ H_2O[/tex]

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