Answer:
q₂ = 0.0002 C
Explanation:
Given that,
Charge, q₁ = -0.0005 C
The force between two charges, F = 9 N
The distance between charges, d = 10 m
We need to find the magnitude of the second charge. The force acting between two charges is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}\\\\q_2=\dfrac{Fr^2}{kq_1}\\\\q_2=\dfrac{9\times (10)^2}{9\times 10^9\times 0.0005}\\\\q_2=0.0002\ C[/tex]
So, the magnitude of the second charge is 0.0002 C.
