Answer:
  h = 6.41 m
Explanation:
For this exercise we use the law of conservation of energy
starting point. When it's on the ramp
    Em₀ = K = ½ m v²
final point. When it is at the highest height
    Em_f = U = m g h
We assume that when it is at the highest height it will stop and possibly return to the ramp
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as there is no friction, the energy is conserved
      Em₀ = Em_f
      ½ mv² = m g h
      h = [tex]\frac{1}{2} \frac{v^2}{g}[/tex]
let's calculate
      h = ½ 11.3² / 9.8
      h = 6.41 m