Answer:
11.186 * 10^3 m/s
Explanation:
For a Veracious to escape the gravitational pull of the earth it has to a attain
Vesc = [tex]\sqrt{\frac{2GM}{R} }[/tex] Â -------- ( 1 )
where: G = ( gravitational constant ) = 6.674 * 10^-11 m^3 kg^-1 s^-2 )
      M = ( mass of earth) =  5.972 * 10^24 kg
      R =  ( Radius of earth ) =  6.371 * 10^6  m Â
next we will Input  values into equation ( 1 )
The required Vesc that the Veracious can attain to escape the gravitational pull of the earth = 11.186 * 10^3 m/s