An object with a mass of 2.00 kg is placed at the end of a spring, having a spring constant of 180.0 N/m. The spring is then compressed 0.890 m. What is the maximum velocity of the mass?

Respuesta :

Answer:

the velocity of the mass is 8.44 m/s

Explanation:

Given;

mass of the object, m = 2 kg

spring constant, k = 180 N/m

extension of the spring, x = 0.89 m

The maximum velocity of the mass is calculated as follows;

By the principle of conservation of energy;

Elastic potential energy = kinetic potential energy

¹/₂kx² = ¹/₂mv²

kx² = mv²

[tex]v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{180 \times 0.89^2}{2} }\\\\v = 8.44 \ m/s[/tex]

Therefore, the velocity of the mass is 8.44 m/s