Write the equation of the following graph in intercept form.


The equation of the following graph, in intercept form, which is provided in the image is,
[tex]f(x)=0.4(x+2)(x-5)[/tex]
The intercept form of parabola can be expressed using the following expression.
[tex]f(x)=a(x-p)(x-q)[/tex]
Here, a is the constant, (p, q) are the x-values on the graph, where y is zero.
In the given graph, the point (-2,0) is the point, where the value y is zero. Here, the value of x is -2. Therefore,
[tex]p=-2[/tex]
The other point, where the value of y is zero is (5,0). Thus the value of q is,
[tex]q=5[/tex]
The value of constant a is,
[tex]a=-\dfrac{p}{q}\\a=-\dfrac{-2}{5}\\a=0.4[/tex]
Put these values in the above equation, we get,
[tex]f(x)=0.4(x+2)(x-5)[/tex]
The equation of the following graph, in intercept form, which is provided in the image is,
[tex]f(x)=0.4(x+2)(x-5)[/tex]
Learn more about the parabola equation intercept form here;
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