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find the angles, θ<0<360, that satisfy the equation below, to the nearest 10th of a degree.

cos(θ)= -√7/5

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sqdancefan

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Answer:

  121.9°, 238.1°

Step-by-step explanation:

One angle is found directly from ...

  θ = arccos(-√7/5) ≈ 121.9°

The other angle is this subtracted from 360°:

  θ = 360° -121.9° = 238.1°

The two angles are 121.9° and 238.1°.

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