Given:
The ratio of 45-45-90 triangle is [tex]x:x:x\sqrt{2}[/tex].
The hypotenuse of the given isosceles right triangle is [tex]7\sqrt{2}[/tex].
To find:
The lengths of the other two sides of the given isosceles right triangle.
Solution:
Let [tex]l[/tex] be the lengths of the other two sides of the given isosceles right triangle.
From the given information if is clear that he ratio of equal side and hypotenuse is [tex]x:x\sqrt{2}[/tex]. So,
[tex]\dfrac{x}{x\sqrt{2}}=\dfrac{l}{7\sqrt{2}}[/tex]
[tex]\dfrac{1}{\sqrt{2}}=\dfrac{l}{7\sqrt{2}}[/tex]
[tex]\dfrac{7\sqrt{2}}{\sqrt{2}}=l[/tex]
[tex]7=l[/tex]
Therefore, the lengths of the other two sides of the given isosceles right triangle are 7 units.
