2. Write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(2,-1) ; y = 3/2x + 6
A. y = -3/2x + 1
B. y = -3/2x - 1
C. y = -3/2x + 2
D. y = -3/2x + 4
y = 3/2x + 6....slope here is 3/2.A parallel line will have the same slope.
y = mx + b slope(m) = 3/2 (2,-1)...x = 2 and y = -1 now we sub and find b, the y int -1 = 3/2(2) + b -1 = 3 + b -1 - 3 = b -4 = b so ur parallel line is : y = 3/2x - 4
