hangely136 hangely136

15-09-2021
Mathematics

contestada

Solve the equation
2h^2-5=27

Respuesta :

KayyyDaaBratt KayyyDaaBratt

15-09-2021

Answer: h= 4, h=-4

step by step-2h^2-5=27

2h^2-5-27=2ℎ2−5−27=0

2h2−5−27=0

2ℎ2−32=0

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