Methane burns in the presence of oxygen to form carbon dioxide and water.
2nd attempt
A sealed chamber contains 7.50 g CH4 and 13.5g 02.
The mixture is ignited producing CO2 and H20. How many grams of CO2 are produced?

Respuesta :

Answer:

= 9.28 g COâ‚‚

Explanation:

First write a balanced equation:

CHâ‚„ + 2Oâ‚‚ -> 2Hâ‚‚O + COâ‚‚

Convert the information to moles

7.50g CHâ‚„ = 0.46875 mol CHâ‚„

13.5g Oâ‚‚ = 0.421875 mol Oâ‚‚

Theoretical molar ratio CHâ‚„:Oâ‚‚ -> 1:2

Actual ratio is  0.46875 : 0.421875 ≈ 1:1

If all CHâ‚„ is used up, there would need to be more Oâ‚‚

So Oâ‚‚ is the limiting reactant and we use this in our equation

Use molar ratio to find moles of COâ‚‚

0.421875 mol Oâ‚‚ * 1 mol COâ‚‚/2 mol Oâ‚‚=0.2109375 mol COâ‚‚

Then convert to grams

0.2109375 mol COâ‚‚ = 9.28114 g COâ‚‚

round to 3 sig figs

= 9.28 g COâ‚‚