Answer:
= 9.28 g COâ‚‚
Explanation:
First write a balanced equation:
CHâ‚„ + 2Oâ‚‚ -> 2Hâ‚‚O + COâ‚‚
Convert the information to moles
7.50g CHâ‚„ = 0.46875 mol CHâ‚„
13.5g Oâ‚‚ = 0.421875 mol Oâ‚‚
Theoretical molar ratio CHâ‚„:Oâ‚‚ -> 1:2
Actual ratio is  0.46875 : 0.421875 ≈ 1:1
If all CHâ‚„ is used up, there would need to be more Oâ‚‚
So Oâ‚‚ is the limiting reactant and we use this in our equation
Use molar ratio to find moles of COâ‚‚
0.421875 mol Oâ‚‚ * 1 mol COâ‚‚/2 mol Oâ‚‚=0.2109375 mol COâ‚‚
Then convert to grams
0.2109375 mol COâ‚‚ = 9.28114 g COâ‚‚
round to 3 sig figs
= 9.28 g COâ‚‚