Respuesta :

Answer:

3t³-8t²-5

Step-by-step explanation:

(3t4 + 12t³-8t³-32t²-5t-20) x[tex]\frac{1}{t+4}[/tex]

(3t³x(t+4)-8t²x(t+4)-5(t+4))x[tex]\frac{1}{t+4}[/tex]

(t+4)x(3t³-8t²-5)x[tex]\frac{1}{t+4}[/tex]