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An ambulance is currently traveling at 25 m/s, and is accelerating with a constant acceleration of 5 m/s^2. The ambulance is attempting to pass a car which is moving at a constant velocity of 50 m/s. How far must the ambulance travel until it matches the car’s velocity?

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Answer:

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Explanation:

Given initial velocity of ambulance

v0=18m/s , acceleration  a=5m/s2  

To find distance,  x=?  

First we need to calculate the time for which it acquires 30\,m/s. For that use equation

v=v0+at  

30=18+5×t  

⇒t=30−185=125seconds  

Distance travelled by the ambulance

x=v0t+12at2  

x=(18×125)+12×5×(125)2  

x=43.2+2.5×5.76=43.2+14.4  

x=57.6m  

Therefore the ambulance has to travel 57.6 m to match the velocity of car.

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