If I earned $2 more than Andrew at the end of the day, then the value of t  is [tex]1\frac{2}{3}[/tex]
Number of hours that I used to work = 1 hour
My hourly pay = Â $3t - 3
My total pay at the end of the day = Number of hours x hourly pay
My total pay at the end of the day = 1 (3t - 3)
My total pay at the end of the day = $ 3t - 3
Number of hours that Andrew used to work = 3t -5 hour
Andrew's hourly pay = Â $2
Andrew's total pay at the end of the day = Number of hours x hourly pay
Andrew's total pay at the end of the day = 2 (3t - 5)
Andrew's total pay at the end of the day = $ 6t - 10
At the end of the day, I earned $2 more than Andrew
My total pay = Andrew's total pay + 2
3t - 3 Â = Â 6t - 10 Â + Â 2
6t  -  3t  =  -3 +10 - 2
3t  =  5
t  =  5/3
[tex]t = 1\frac{2}{3}[/tex]
If I earned $2 more than Andrew at the end of the day, then the value of t  is [tex]1\frac{2}{3}[/tex]
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