A 2.1 × 103
kg car accelerates from rest under
the action of two forces. One is a forward
force of 1141 N provided by traction between
the wheels and the road. The other is a 911 N
resistive force due to various frictional forces.
How far must the car travel for its speed to
reach 2.9 m/s?
Answer in units of m.
First solve the acceleration of the car using the formula
Fnet = ma
Where Fnet is the net force acting on the body
M of the object
A is the acceleration
( 1141 – 911) = (2.1 x10^3) a
a = 0.1095 m/s2
