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A circle has diameter 18 inches, and a chord is 14 inches long. What is the distance in inches from the chord to the center of the circle, to the nearest hundredth?

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Answer:

Let O be the center of a circle whose radius is r cm , in which AB= 14 cm long

cord is at a distanceof 24 cm from O. Draw a perpendicular OD on AB , thus ,

OD= 24 cm.

In right angled triangle. ODB

OB^2 = OD^2+ DB^2

r^2 =(24)^2+(AB/2)^2 = 576+(14/2)^2

r^2 = 576+ 49=625

r = √625. =25 cm. Answer.