aamy
aamy
12-01-2017
Mathematics
contestada
The first four terms
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Аноним
Аноним
12-01-2017
an1 = 3n^2 -7 = 3(1)^2 -7 = 3(1)-7 = -4
an2 = 3n^2 -7 = 3(2)^2 -7 = 3(4)-7 = 5
an3 = 3n^2 -7 = 3(3)^2 -7 = 3(9)-7 = 20
an4 = 3n^2 -7 = 3(4)^2 -7 = 3(16)-7 = 41
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