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Two groups of tourists are on the same floor of a skyscraper they are visiting, and they board adjacent elevators at the same time. The first group is headed up at a speed of 140 meters per minute. The second is headed down at a speed of 290 meters per minute. How long will it be before the elevators are 360 meters apart?


Ne me faites pas perdre mon temps, s'il vous plait ! J'ai besoin de ça de toute urgence !

Respuesta :

Let time be x distance be y

  • 140x=y-(1)
  • 290x=360-y-(2)

Put value in eq(2)

[tex]\\ \rm\longmapsto 290x=360-(140y)[/tex]

[tex]\\ \rm\longmapsto 440x=360[/tex]

[tex]\\ \rm\longmapsto x=1.2min[/tex]

Put it in eq(1)

  • d=1.2(140)=168m

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