alexayero
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A 2kg rock is at the edge of a cliff 20m above the surface of a lake. It comes loose and falls. Half way down it is falling at 14 m/s. What is its Kinetic Energy at the half way point?

Please show work!

Respuesta :

fieryanswererft

Answer:

196 Joules

Explanation:

kinetic energy = 1/2 * mass * velocity²

Given:

  • mass: 2 kg
  • velocity: 14 m/s

using formulae:

[tex]\rightarrow \sf kinetic \ energy = \dfrac{1}{2} * 2 * 14^2[/tex]

[tex]\rightarrow \sf kinetic \ energy = 196 \ J[/tex]

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