contestada

Every year in Delaware there is a contest where people create cannons and catapults designed to launch pumpkins as far in the air as possible. The equation y = 15 + 110x – 16x2 can be used to represent the height, y, of a launched pumpkin, where x is the time in seconds that the pumpkin has been in the air. What is the maximum height that the pumpkin reaches? How many seconds have passed when the pumpkin hits the ground? (Hint: If the pumpkin hits the ground, its height is 0 feet.)

Respuesta :

Answer:

See below

Step-by-step explanation:

y = - 16x^2 + 110x + 15    is a dome shaped parabola

  max will occur at x = -b/2a = -  110/(2*-16) = 3 7/16   seconds

     using this value in the equation results in y = 204  units  (feet?)

Height = 0 = -16x^2 +110x + 15     use quadratic formula

                                  with  a = -16    b = 110    c = 15    to find  7 seconds

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