The equation given is matched with the respective vertex forms.
The standard equation for a circle is given by
(x-h)² + (y-k)² = r²
The equation given in the question are
x² + y²  − 4x + 12y − 20 = 0
(x − 6)²  + (y − 4)²  = 56
x²  + y²  + 6x − 8y − 10 = 0
(x − 2)²  + (y + 6)²  = 60
3x²  + 3y²  + 12x + 18y − 15 = 0
(x + 2)²  + (y + 3)²  = 18
5x²  + 5y²  − 10x + 20y − 30 = 0
(x+3)²  + (y-4)²  = 35
2x²  + 2y²  − 24x − 16y − 8 = 0
(x-1)²  + (y+2)²  = 11
The first equation is
x² + y²  − 4x + 12y − 20 = 0
It can be written ad
x² -4x + 4 - 4 +y²+12y +36-36 -20 = 0
(x-2)² +(y+6)²= 60
The second equation is
x²  + y²  + 6x − 8y − 10 = 0
x² +6x +9-9 +y²  -8y +16-16 -10 = 0
(x+3)²  + (y-4)²  = 35
The third equation is
3x²  + 3y²  + 12x + 18y − 15 = 0
(x + 2)²  + (y + 3)²  = 18
The fourth equation is
5x²  + 5y²  − 10x + 20y − 30 = 0
(x-1)²  + (y+2)²  = 11
The fifth equation is
2x²  + 2y²  − 24x − 16y − 8 = 0
(x − 6)²  + (y − 4)²  = 56
To know more about standard equation of Circle
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