The equation of the line that passes through the point (-4 , 3) with slope ā2 is:
y = ā2x ā 5
Given the points are (ā4 , ā3) and (4 , 1)
The gradient of the line through the points' locations (xā , yā) and (xā , yā) is: Ā yā ā yā/xā ā xā
Substitute the given points in the above formula:
=1 ā(ā3)/4 ā (ā4)
=4/8
=1/2
If the product of the slopes of two perpendicular lines is -1, then the slope of the perpendicular line is ā1/1/2 = ā2
Therefore the line that passes through the point (-4 , 3) with slope ā2 has equation:
y ā 3 = ā2(x ā 4)
y = ā2x ā 8 ā 3
y = ā2x ā 5
Hence we get the expression as y = ā2x ā 5
Learn more about "intercept forms" here-
brainly.com/question/6202710
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