a sample of ar gas has a volume of 5.10 l with an unknown pressure. the gas has a volume of 9.29 l when the pressure is 2.65 atm , with no change in temperature or amount of gas.

Respuesta :

With no change in temperature or amount of gas, the pressure of ideal gas approximation is 4.83 atm.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

V1 = 5.1 L

V2 = 9.29 L

P2 = 2.65

When the initial and final temperature is the same, we can use the ratio of pressure and volume as

P1 . V1 = P2 . V2

P1 . 5.1 = 2.65 . 9.29

P1 = 4.83 atm

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