Solution: x1 =9 x2 = - 7
In that case, we identify values of a, b and c
a = 1
b = -2
c = -63
Let's use the quadratic formula
[tex]\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ \\ x\text{ }=\text{ }\frac{2\text{ }\pm\sqrt{(-2)^2-4(1)(-63)}}{2(1)} \\ \\ x\text{ = }\frac{2\pm\sqrt{4+252}}{2} \\ \\ x\text{ }=\text{ }\frac{2\pm16}{2} \\ \\ x_1\text{ }=\frac{18}{2}\text{ } \\ x_1=9 \\ x_2\text{ }=\text{ }\frac{-14}{2} \\ x_2=-7 \end{gathered}[/tex]