Given: The quadrilateral PQRS
To Determine: The value of QS
Solution
Please note that the diagonal of a quadrilaterals bisect each other. This is as shown below
Therefore ST equals QT
[tex]\begin{gathered} ST=QT \\ 6x+3=4x+27 \\ 6x-4x=27-3 \\ 2x=24 \\ x=\frac{24}{2} \\ x=12 \end{gathered}[/tex][tex]\begin{gathered} QS=ST+QT \\ QS=6x+3+4x+27 \\ QS=10x+30 \\ QS=10(12)+30 \\ QS=120+30 \\ QS=150 \end{gathered}[/tex]
Hence QS = 150
