The flow rate of the water in the pipe is given by Q=Av
where
Q is the flow rate
A is the cross-sectional area of the pipe
v is the speed of the water
with the help of question,
,
Q=1.20m3/s
the radius of the pipe is
r = 0.160 m
So, the cross-sectional area is
;
;A=πr^2 where r=0.160mm
=π(0.160×0.160)2=0.0256m
So we can re-arrange the equation to find the speed of the water:
;v=Q/A=1.20m3/s/0.0256
=4687.5m3
To know more about area of pipe visit
https://brainly.com/question/19211820
#SPJ1
