RudyLopez
contestada

Find the number of real number solutions for the equation. x² + 26 = 0 ☺☻

A.) Can not be determined from the graph
B.) 2
C.) 0
D.) 1

Respuesta :

x^2+26=0
So x^2=-26
now x=squareroot(-26)
Since the value of x is squareroot(-26) which is not a real number and is a imaginary number so roots does not exist for this equation.
So option c 0 real roots is correct

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