bnielsen01 bnielsen01
  • 12-04-2017
  • Mathematics
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Find the Inverse of 3x^3-1=y

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Sxerks Sxerks
  • 12-04-2017
[tex]y = 3x^{3} - 1[/tex]
[tex]x = 3y^{3} - 1[/tex]
[tex]3y^{3} = x + 1[/tex]
[tex]y^{3} = \frac{x + 1}{3}[/tex]

[tex]y = \sqrt[3]{\frac{x + 1}{3}}[/tex]
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