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In the figure, one side of the rectangle divides the circle in half.
What is the area of the unshaded portion of the figure?
Enter your answer to the nearest tenth please

In the figure one side of the rectangle divides the circle in half What is the area of the unshaded portion of the figure Enter your answer to the nearest tenth class=

Respuesta :

It would be about 60, correct? 
JonHenderson55
The answer is:  50.2 ft² .
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Explanation:
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The answer would be the area of the rectangle:  12 ft * 5 ft = 60 ft² ;

MINUS {"1/2" of  the area of the circle).
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The area of the circle, "A":  A = π r² .

π ≈ 3.14 ;  "r", the radius, is 1/2 the diameter of the circle.
                    The diameter of the circle is:  5 ft.  

r = (1/2) * (5 ft) = (2.5 ft).

A = π r² = (3.14) * (2.5 ft)² = (3.14) * (2.5 ft) * (2.5 ft) = 19.625 ft² = 19 5/8 ft² .

1/2 the area of the circle;  which is the shaded region;  is:
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 (19.625 ft²) / 2  =  9.8125 ft²  = 9  11/16 ft².
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The area of the unshaded region is:

60 ft²  − 9.8125 ft²  =  50.1875 ft² ;  → round to the nearest tenth →  50.2 ft² .
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