6,000 dollars is invested in two different accounts earning 3% and 5% interest. At the end of one year, the two accounts earned $220 in interest. How much money was invested at 5%?
time is 1 year so t=1 r=0.03 ad 0.05 we want to find 5% so x is wha we solve for
the interests are 0.03(6000-x) and 0.05x they add to 220 220=0.03(6000-x)+0.05x 220=180-0.3x+0.05x 220=180+0.02x minus 180 both sides 40=0.02x divide both sides by 0.02 2000=x $2000 was invested at 5%
