oakgrove31mlb oakgrove31mlb

15-06-2017
Mathematics

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What is the equation of the line that passes through (–2, –3) and is perpendicular to 2x – 3y = 6

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steve77 steve77

15-06-2017

2x - 3y = 6
3y = 2x - 6
y = (2/3)x - 2

gradient of line = -1 / (2/3) = -3/2

Eqn of line:
y = (-3/2)x + c

substitute x = -2, y = -3

-3 = (-3/2)(-2) + c
c = -6

Thus eqn of line is
y = (-3/2)x - 6

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