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Find the quotient of the quantity [tex]
\frac{4x^3y+12x^2y^3-20xy}{4xy} [/tex].

A.[tex]
x^2+3xy^2+5[/tex]

B. [tex]
x^2+3xy-5[/tex]

C. [tex]
4x^3y+12x^2y^3-5[/tex]

D. [tex]
x^2+3xy^2-5[/tex]

Please tell me how to get the correct answer! Thank you!

Respuesta :

apologiabiology
we need to factor out the things like in distributive
remember ab+ac=a(b+c)
so

[tex]\frac{4x^3y+12x^2y^3-20xy}{4xy}=[/tex]
[tex]\frac{(4xy)(x^2)+(4xy)(3xy)+(4xy)(-5)}{4xy}=[/tex]
[tex]\frac{(4xy)(x^2+3xy-5)}{4xy}=[/tex]
[tex]x^2+3xy-5[/tex]


answer is B

Answer:

answer:b

Step-by-step explanation:

we need to factor out the things like in distributive

remember ab+ac=a(b+c)

so