To solve the problem:
Let x be m ∠ADB.
Because m ∠BDC is 32° greater than m ∠ADB, thereforem ∠BDC = x + 32°
Each angle of a rectangle is 90°, therefore:
x + (x + 32) = 90
2x + 32 = 90
2x = 58
x  = 29°
x + 32 = 61°
Answer:
m ∠BDC = 61°
m ∠ADB = 29°