Respuesta :

[tex]\bf r(x)=\cfrac{3x-2}{2x+5}\implies \cfrac{dr}{dx}=\stackrel{quotient~rule}{\cfrac{3(2x+5)~~-~~(3x-2)2}{(2x+5)^2}} \\\\\\ \cfrac{dr}{dx}=\cfrac{\underline{6x}+15\underline{-6x}+4}{(2x+5)^2}\implies \cfrac{dr}{dx}=\cfrac{19}{(2x+5)^2}[/tex]