A rectangular garden has a perimeter of 172 feet. The length of the garden is 24 feet more than the width. What are the dimensions of the garden? (Recall the formula P = 2L + 2W.)
a.62 ft by 86 ft
c.55 ft by 79 ft
b.31 ft by 55 ft
d.74 ft by 98 ft
Given width is 24 less than length. W=L-24 Perimeter = 2(W+L)=2(L-24+L)=4L-48Â But we're also given perimeter = 172' Therefore 4L-48=172 solve for L 4L=172+48=220 L=55' W=55-24 =Â 31' Check: Perimeter = 2(W+L)=2(31+55)=2*86=172'Â good!
Answer: The dimensions of the garden are 31' * 55'
