a child riding a bicycle at 15 m/s decelerate at the rate of 3.0 meters per second squared for 4.0 seconds. what is the child's speed at the end of the 4.0 seconds?
3m/[tex] s^{2} [/tex] of deceleration for 4 seconds. 3 x 4 = 12 15 - 12 = 3 The child will be riding a bicycle at 3m/s after 4 seconds.
If you want a full equation (which you might not): let a be acceleration rate, Vf be final velocity, Vi as initial velocity, and t as time. a = (Vf - Vi)/t let's fill in everything we know now:
