Respuesta :
To determine if the reaction provided is electrically possible, we can first separate the overall reaction into its half-reactions:
Mg (s) + Brā (l)Ā ā MgBrāĀ
MgĀ ā Mg²⺠+ 2eā»Ā Ā Ā Ā Ā Ā E = -2.37 V
Brā + 2eā»Ā ā 2Brā»Ā Ā Ā Ā Ā Ā E = 1.09 V
Looking at the half-reactions, we can see that magnesium loses electrons in the process which means that magnesium isĀ oxidized.
Since bromine is gaining electrons, Brā is beingĀ reduced.
Now to determine if this reaction is taking place, we must find the reduction potentials for each half-reaction. To final the overall potential of the cell, we take the difference in the cathode (reduction) and anode (oxidation) potentials.
Ecell = Ecathode - Eanode
Ecell = 1.09 V - (-2.37 V)
Ecell = 3.46 V
A positive value of Ecell means that the reaction will happen spontaneously. Therefore, this reaction is electrically possible and will take place.
Mg (s) + Brā (l)Ā ā MgBrāĀ
MgĀ ā Mg²⺠+ 2eā»Ā Ā Ā Ā Ā Ā E = -2.37 V
Brā + 2eā»Ā ā 2Brā»Ā Ā Ā Ā Ā Ā E = 1.09 V
Looking at the half-reactions, we can see that magnesium loses electrons in the process which means that magnesium isĀ oxidized.
Since bromine is gaining electrons, Brā is beingĀ reduced.
Now to determine if this reaction is taking place, we must find the reduction potentials for each half-reaction. To final the overall potential of the cell, we take the difference in the cathode (reduction) and anode (oxidation) potentials.
Ecell = Ecathode - Eanode
Ecell = 1.09 V - (-2.37 V)
Ecell = 3.46 V
A positive value of Ecell means that the reaction will happen spontaneously. Therefore, this reaction is electrically possible and will take place.
Answer:
The correct answers are Mg is oxidized, Br2 is reduced, and yes this redox reaction can take place.