Respuesta :

Jr04
(8x^9y^3)^-2 (6x^7y^7) simplify. write the answer using positive exponents only

[tex](8x^9y^3)^{-2} (6x^7y^7)= \\ \\ \\ (8)^{-2} (x^9) ^{-2}( y^3)^{-2} (6)(x^7)(y^7)= \\ \\ \\ (8)^{-2} (x) ^{9-2}( y)^{3-2} (6)(x^7)(y^7)= \\ \\ \\ (8)^{-2} (x) ^{9-2+7}( y)^{3-2+7} (6)= \\ \\ \\ 6*(8)^{-2} (x) ^{14}( y)^{8} = \\ \\ \\ \dfrac{6}{64} x ^{14} y^{8} = \boxed{\dfrac{3}{32}\ x ^{14} y^{8} } [/tex]

Otras preguntas